Question

dimensional analusis v2=u2+2as

Answer 1

Answer:

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We have v2−u2=2as.

Checking the dimensions on both sides, we get

LHS=[LT−1]2−[LT−1]2

=[L2T−2]−[L2T−2]=[L2T−2]

RHS=[L1T−2][L]=[L2T2]

Comparing LHS and RHS, we find LHS = RHS.

Hence, the formula is dimensionally correct.

Explanation:

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Answer 2

Explanation:

ANSWER

Since, v

2

−u

2

=2 as

⇒ v

2

=u

2

+2 as

∴ [v]=[u]= velocities

=[M

0

L

1

T

−1

]

a= acceleration ,[a]=[M

0

L

1

T

−2

]

s= distance, [s]=[M

0

L

1

T

0

]

hence LHS:−[v]

2

=[M

0

L

1

T

−1

]

2

=[M

0

L

2

T

−2

].....(1)

u

2

=[M

0

L

1

T

−1

]

2

=[M

0

L

2

T

−2

].......(2)

and

[2 as]=[M

0

L

1

T

−2

][M

0

L

1

T

0

]9

=[M

0

L

2

T

−2

].........(3)

Two quantities can be added / Subtracted only when having same dimension.

From equation (A),(1),(2),(3)

LHS=RHS

Answer by # pratha

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