Question

dimensional analysis of acceleration​

Answer 1

ExplanationDimension of acceleration is [a] = L/T^2

Answer 2

The dimension formula of acceleration is mentioned below:

We know that,

• ${\small{\underline{\boxed{\pmb{\sf{\vec{a} \: = \dfrac{\Delta \vec{v}}{t}}}}}}}$

Where, a denotes acceleration, ∆v denotes change in velocity and t denotes time taken.

Therefore,

$:\implies \sf Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ :\implies \sf a \: = \dfrac{\Delta v}{t} \\ \\ :\implies \sf a \: = \dfrac{s}{t \times t} \\ \\ :\implies \sf a \: = \dfrac{s}{t^2} \\ \\ :\implies \sf a \: = \dfrac{[L]}{[T]^{2}} \\ \\ :\implies \sf a \: = M^0L^1T^{-2}$

• Henceforth, solved!