Question

Dimensional analysis of the fourth equation of motion.
i.e. S=u+a/2(2n-1)
Where u is initial velocity
a is the acceleration
n is the time .

Answer 1

Explanation:

i.e S(nth) = [L]/[T] = [LT^-1] dimensionally. RHS. Now, U+(1/2)*a*(2n-1) = where,. U= initial velocity = [LT^-1]. a= acceleration = [LT^ -2].