Question

Dimensional formul
a for I=r×F

Answer 1

First of all we have to find out dimension of L and R .
We know, relation L answer energy is E = 1/2Li² 
so, dimension of L = dimension of energy/dimension of i²
= [ML²T⁻²]/[A²] = [ML²T⁻²A⁻²] 

Similarly we know, relation between R and energy is E = i²Rt 
So, dimension of R = dimension of E/dimension of i²t
= [ML²T⁻²][A²T] = [ML²T⁻³A⁻²]

Now, dimension of L/R = dimension of L/dimension of R 
= [ML²T⁻²A⁻²][ML²T⁻³A⁻²] = [T] 

Hence, answer is [T]




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