Question

Dimensional formula of gravitational head

Answer 1

Answer:

if for fluid \frac{hρg}{ρg}

Explanation:

so \frac{hρg}{ρg}=h;

which implies the dimensional formlula is [M^0L^1T^0]

here ρ is density of fluid

        g is accleration due to gravity

Answer 2

Answer:f = Gm1m2/d*d

G = f*d*d/m1m2

[mlt-2][l*l]/[m*m]

[m-1l3t-2]

Explanation: