Question

Dimensional formula of radius ??

Answer 1

$answer$

[2πr]=[2]⋅[π]⋅[r]=1⋅1⋅L=L, since the constants 2 and π are both dimensionless and the radius r is a length.

Answer 2

Answer:

2πr]=[2]⋅[π]⋅[r]=1⋅1⋅L=L, since the constants 2 and π are both dimensionless and the radius r is a length.

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