Question

DIMENSIONALLY ANALYZE V^{2}=U^{2}+2AS

Answer 1

Answer:

V= final velocity = [LT-¹]

u= initial velocity=[LT-¹]

a= acceleration =[LT-²]

s= distance= [L]

v²=u²+ 2as

=>v²-u²=2as

[LT-¹]²-[LT-¹]²=2[LT-²][L]

[L²T-²][L²T-²]=2[L²T-²]

2[L²T-²]=2[L²T-²]

2 is dimensionless

hence proved

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