Question

Dimensions of a brick are 20cm multiply 5cm multiply 3cm. What is the weight of this brick in gf. Calculate maximum and minimum pressure exerted by the brick. Density of brick material=6.5g/cm^3

Answer 1

Answer:

let do this as a relation mg is the wight

we ahve density that is mass by volume and pressure that is weight by area

mass is 6.5*20*5*3=1950 gram=1.96 kg and weight is 19.50

minimum pressure is 195o0/100=195

and maximum is 1300

Explanation:

Answer 2

Weight of the brick = 1950 gf, Minimum pressure = 19.5 gf/cm² and Maximum pressure = 130 gf/cm²

Given:

Dimensions of brick = 20 cm x 5 cm x 3 cm

Density of brick = 6.5 g/cm³

To find: weight of brick in gf

Maximum and minimum pressure exerted by the brick

Solution:

Volume of brick = 20 cm x 5 cm x 3 cm = 300 cm³

Density of brick = 6.5 g/cm³

⇒ Mass of brick = 6.5 x 300 = 1950 g

⇒ Weight of the brick = 1950 gram-force

Now,

pressure = force/area

⇒ if force is constant, then the minimum area will exert maximum pressure and the maximum area will exert minimum pressure (inverse proportionality)

⇒ Minimum area = 20 x 5 = 100 cm²

Maximum area = 5 x 3 = 15 cm²

⇒ Minimum pressure = 1950/100 = 19.5 gf/cm²

Maximum pressure = 1950/15 = 130 gf/cm²

∴ Weight of the brick = 1950 gf, Minimum pressure = 19.5 gf/cm² and Maximum pressure = 130 gf/cm²