dimensions of a closed wooden box in the ratio 5 : 4 : 3 . if the cost of painting its outer surface excluding the base at the rate of Rs 5 per dm² is Rs9250. find the dimensions of the box .
Answers
Area =9250/5
=1250
Let the dimensions be 5x 4x and 3x
5x+4x+3x=1250
12x=1250
X=1250/12
=104.16
Substitute X with 104.16 and you will get the ans
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Answer:
Length=125dm, Breadth=100dm, Height=75dm
Step-by-step explanation:
Given external dimensions of a closed wooden box are in the ratio 5:4:3.if the cost of painting its outer surface at the rate of Rs 5 per dm^2dm2 Rs 11750. we have to find the dimension of box.
Let length=5x, breadth=4x and height=3x
T.S.A=2(LB+BH+HL)2(LB+BH+HL)
=2(5x\times 4x+4x\times 3x+3x\times 5x)2(5x×4x+4x×3x+3x×5x)
=2(20x^2+12x^2+15x^2)=94x^22(20x2+12x2+15x2)=94x2
Also given outer surface at the rate of Rs 5 per dm^2dm2 Rs 11750.
∴ T.S.A=5(11750)=58750dm^2T.S.A=5(11750)=58750dm2
Hence, equating we get
94x^2=5875094x2=58750
⇒ x^2=625x2=625 ⇒ x=25
Hence, Length=5x=5(25)=125dm
Breadth=4x=4(25)=100dm
Height=3x=3(25)=75dm