Math, asked by sumagk2101, 3 months ago

dimensions of a rectangle with the perimeter of 26 cm and an area of 42 square cm?dimensions of a rectangle with the perimeter of 26 cm and an area of 42 square cm?

Answers

Answered by mskn71
2

l*b =42 ---l= 42/b put this in equation...2(4

Attachments:
Answered by syedafakhra
0

Answer:

L=6

B=7

Step-by-step explanation:

from perimeter

26=2(l+b)

13=l+b

l=13-b

from area

42=l×b

42=(13-b) ×b

42=13b-b^2

b^2-13b+42=0

b will be equal to 7

and l =6

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