dimensions of a room are 12 metre * 8 metre * 6 metre find the cost of whitewashing its four walls and ceiling
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Answer:
Area of walls=
12(length)*6(height)*2(opp walls are of same dimensions. So multiplied by two) =144
Similarly other two opposite walls =8*6*2=96
Area of ceiling=8(breadth)*12(length)=96
Total area=96+96+144=336
Cost of whitewashing = 336*cost of painting unit area
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2(lb+bh+hl)×cost of white wash per meter square
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