Question

Dimensions of a room are 8*4*2 m how long an iron rod can be placed

Answer 1

Answer:

2√21m

Step-by-step explanation:

length of diagonal=√(l²+b²+h²)

Answer 2

Answer:

2$\sqrt{21}$ m

Step-by-step explanation:

length of diagonal= $\sqrt{(l^{2}+b^{2} +h^{2}) }$ = longest iron rod that can be placed in the room.

= $\sqrt{8^{2}+4^{2} +2^{2} }$ m

= $\sqrt{64+16+4}$ m

= $\sqrt{84}$ m

= 2$\sqrt{21}$ m.