Question

dimensions of class room are 20 feet * 20 feet * 12feet
helpet Find the sum of the areas of its floor and four walls​

Answer 1

Answer:

1360 feet^2

Step-by-step explanation:

Area of base (floor) = 20 feet * 20 feet

= 400 feet^2

and, Area of 4 walls = 4 ( 20 feet * 12 feet)

= 960 feet^2

Therefore,

Required sum = 400 feet^2 + 960 feet^2

= 1360 feet^2

Answer 2

Answer:

area of four walls = 2(l+b).h

area of roof and floor = lb + lb = 2 lb

a/c to question,

2(l+b).h = 2lb

(l+b)h = lb

(20+16).h = 20×16

36h = 320

h = 320/36 =80/9 = 8.89m

Hope it helps