Dimensions of resistance in an electrical circuit, in. terms pf dimension of mass M, of length L, of time T and of current l, would be [AIPMT (Prelims)-2007) (1) [ML-T-31-2] (2) [MLPT-3H-] (3) [ML?T-] (4) [ML?T-1]
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Answer:
[AIPMT (Prelims)-2007) (1) [ML-T-31-2] (2) [MLPT-3H-] (3) [ML?T-] (4) [ML?T
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[ML²T^-³A^-²]
Explanation:
According to the Ohm's Law
- R = V/I Where V= Voltage, I= Current, R= Resistance
And we know,
- V= W/q Where W= Work, q= Charge
- q= It Where t= time
We know, W= F.S = m.a.S
So [W]= [ML²T^-²]
[q]= [A.T]
Hence, [V]= [ML²T^-³A^-¹]
Therefore the dimension of Resistance, R is
[R]= [ML²T^-³A^-¹]/[A]
= [ML²T^-³A^-²]
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