Physics, asked by khairunnisha8477, 7 hours ago

Dimensions of resistance in an electrical circuit, in. terms pf dimension of mass M, of length L, of time T and of current l, would be [AIPMT (Prelims)-2007) (1) [ML-T-31-2] (2) [MLPT-3H-] (3) [ML?T-] (4) [ML?T-1] ​

Answers

Answered by mehermohit690
4

Answer:

[AIPMT (Prelims)-2007) (1) [ML-T-31-2] (2) [MLPT-3H-] (3) [ML?T-] (4) [ML?T

Answered by jubayerhabib040
0

[ML²T^-³A^-²]

Explanation:

According to the Ohm's Law

  • R = V/I Where V= Voltage, I= Current, R= Resistance

And we know,

  • V= W/q Where W= Work, q= Charge

  • q= It Where t= time

We know, W= F.S = m.a.S

So [W]= [ML²T^-²]

[q]= [A.T]

Hence, [V]= [ML²T^-³A^-¹]

Therefore the dimension of Resistance, R is

[R]= [ML²T^-³A^-¹]/[A]

= [ML²T^-³A^-²]

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