Question

Dimensions of specific heat are(a) [ML²T⁻²K](b) [ML²T⁻²K⁻¹](c) [ML²T²K⁻¹](d) [L²T⁻²K⁻¹]

Answer 1

Options D)

${ {l}^{2} {t}^{ - 2} {k}^{ - 1}$

Answer 2

Answer:

D) L² T⁻² K⁻¹.

Explanation:

Unit of Heat = Joule

Heat Energy(Q) = m × c × Δt

where, m is the mass of the body, c is the specific heat capacity and Δt is the change in temperature.

Therefore, c = Q/mΔt

= N × m.

= kg ms⁻² × m

= kg m² s⁻²

Thus, the dimension of Q = M L² T⁻²

Dimensions of Specific Heat Capacity -

[c] = (M L² T⁻²) ÷ (M K) [ The dimension of temperature being K]

 [c] = L² T⁻² K⁻¹

Hence, the Dimensions of Specific Heat Capacity c is L² T⁻² K⁻¹.