Question

Dimensions of surface tension is
(A) [M¹L⁻¹T⁻¹] (B) [M¹L⁰T⁻²]
(C) [M¹LT⁻¹] (D) [M²L²T⁻¹]

Answer 1

$hii... \\ \\ surface \: tension = \frac{force}{length} \\ \\ force = [ml {t}^{ - 2}] \\ length =[ l ]\\ \\ so..surface \: tension = \frac{ml {t}^{ - 2} }{l} = > [m {t}^{ - 2}] \\ \\ that \: can \:also \: be \: written \: as \: [{m}^{1} {l}^{0} {t}^{ - 2}] \\ \\ so \: correct \: option \: is \: B \: option \: \\ \\ hope \: this \: helps :)$

Answer 2

Hay dear

According to the question we know that formula

Surfaces tension = f / l.

so,

mlt-²/l. = mt-²

Then, we can also write it as m¹ l^0 t-²

So, the correct options is b

I hope it's help you ☺