Question

Dimensions of the expression EL^2/M^2.G^2 where E=Energy,L=Angular momentum,M=Mass,G=Gravitational constant​

Answer 1

Answer:

According to the problem,expression is P=El

2

m

−5

G

−2

where E is energy [E]=[ML

2

T

−2

], m is mass [m]=[M]

L is angular momentum [L]=[ML

2

T

−1

], G is gravitational constant [G]=[M

−1

L

2

T

−2

]

Substituting dimensions of each physical quantity in the given expression,

[P]=[ML

2

T

−2

]×[ML

2

T

−1

]×[M]

−5

×[M

−1

L

3

T

−2

]

−2

=[M

1+2−5+2

L

2+4−6

T

−2−2+4

]

[M

0

L

0

T

0

]

This shows that P is dimensionless quantity.

Explanation:

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