Question

dind the value of which one root of the quadratic equation
[tex]4 {x}^{2} + px + 3 = 0
​is 6time the other

Answer 1

Answer:

Roots (1/√2, 3√2) or, (-1/√2, -3√2)

Step-by-step explanation:

Given, x²+px+3=0

A/Q, 1st root = x and 2nd root = 6x

Now,

1st root × 2nd root = C/A

or,

x×6x = 3/1

or,

6x² = 3 , x² = 1/2 , x = ±1/√2.

so,

1st root = 1/√2 or -1/√2 and

2nd root = 6/√2 = 3√2 or -6/√2 = -3√2.