Math, asked by Hoinubaite, 2 months ago

Dinesh has a total of Rs.590 currency note.in the denomination of 250, Rs 20 is 3:5. if he has a total of 25 notes , how many notes of it's denomination he has?​

Answers

Answered by DaDDyCaLLinG89
0

Answer:

Step-by-step explanation:

Given Dinesh has 590 Rupees

RS50,20&10 are there ⇒ Total 25 notes

Rs50&Rs20 ⇒3:5

Notes of Rs50=3x

Notes of Rs20=5x

Notes of Rs10=25−(3x+5x)=25−8x.

Amount in 50 Rupee notes ⇒50×3x=150x

Amount in 20 Rupee notes ⇒20×5x=100x.

Amount in 10 Rupee notes ⇒10(25−8x)=250−80x

Total Amount =590  

⇒150x+100x+250−80x=590

⇒250−80x=590−250

⇒170x=340

∴x=2

So Denesh has

Notes of Rs.50=3(2)=6i.e;150(2)=300Rs.

Notes of Rs.20=5(2)=10i.e;100(2)=200Rs.

Notes of Rs.10=25−8(2)=9i.e;=90Rs

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Answered by shobhacdhage
0

Answer:

no of notes =10=25-8(2)9i.e= 90rs

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