Math, asked by Anonymous, 8 months ago

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?​

Answers

Answered by Anonymous
35

Answer:

\huge\underbrace\mathfrak\red{Answer:-}

Total distance travelled by Dinesh = AB + BC

= 7.5km + 12.7km

= 20.2 km

Total distance travelled by Ayub = AD + DC

= 9.3km + 11.8 km

= 21.1 km

Hence Ayub travelled More distance than Ayub as 21.1 > 20.2

The difference between path travelled by them = 21.1km - 20.2 km

= 0.9 km.

Hence Ayub travelled 0.9 km more than Dinesh.

Answered by ItzNavLoey
33

\huge\bf\underline\green{QuesTion}

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

\huge\bf\underline\green{AnsWer}

\rm{Distance ~covered ~by ~Dinesh}

\rm{= ~AB ~+ ~BC}

\rm{= ~7.5 ~+ ~12.7}

\rm{= ~20.2 ~km}

\rm{Distance ~covered ~by ~Ayub}

\rm{= ~AD ~+ ~DC}

\rm{= ~9.3 ~+ ~11.8}

\rm{= ~21.1 ~km}

\rm\underline{Who ~covered ~more~ distance?}

\rm{➝~21.1~-~20.2~=~0.9~km}

\rm\pink{➝~Ayub~ covered ~0.9 ~km ~more~ distance~ than~ Dinesh}

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