Math, asked by mauryangupta, 3 months ago

Dinesh went from place A to place B and from
there to place C. A is 7.5 km from B and B is A
12.7 km from C. Ayub went from place Ato place
D and from there to place C. D is 9.3 km from AA
and C is 11.8 km from D. Who travelled more
and by how much?​

Answers

Answered by nafisaa731
1

Answer:

Distance travelled by Dinesh = AB + BC = 7.5+12=19.5

Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1

Ayub travelled more than Dinesh .

difference=21.1-19.5=1.6

He travelled 1.6 km more than Dinesh

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