Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
Answers
Answered by
246
dhinesh travelled = A to B + B to C
= 7.5 + 12.7
= 20.2 km
ayub travelled = A to D + D to C
= 9.3 + 11.8
= 21.1
thus ayub travelled more distance than dhinesh
= 7.5 + 12.7
= 20.2 km
ayub travelled = A to D + D to C
= 9.3 + 11.8
= 21.1
thus ayub travelled more distance than dhinesh
Answered by
182
Given that:-
- Dinesh went from place A to place B and from there to place C.
- A is 7.5 km from B and B is 12.7 km from C.
- Ayub went from place A to place D and from there to place C.
- D is 9.3 km from A and C is 11.8 km from D.
To find:-
- Who travelled more and by how much?
_____________________________
From the question, it is given that,
Distance travelled by Dinesh = AB + BC
= 7.5 + 12.7
= 20.2 km
∴Dinesh travelled 20.2 km
Distance travelled by Ayub = AD + DC
= 9.3 + 11.8
= 21.1 km
∴Ayub travelled 21.1km
Therefore, Ayub travelled more distance by = (21.1 – 20.2)
= 0.9 km
∴Ayub travelled 0.9 km more than Dinesh.
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