Math, asked by Li8z3aapkataBalasu, 1 year ago

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Answers

Answered by vikhashini
246
dhinesh travelled = A to B + B to C
                            = 7.5 + 12.7
                            = 20.2 km
 ayub travelled     = A to D + D to C
                            = 9.3 + 11.8
                            = 21.1
thus ayub travelled more distance than dhinesh



Answered by xItzKhushix
182

\huge\mathscr{\underline{Explanation:}}

Given that:-

  • Dinesh went from place A to place B and from there to place C.

  • A is 7.5 km from B and B is 12.7 km from C.

  • Ayub went from place A to place D and from there to place C.

  • D is 9.3 km from A and C is 11.8 km from D.

To find:-

  • Who travelled more and by how much?

_____________________________

From the question, it is given that,

Distance travelled by Dinesh = AB + BC

= 7.5 + 12.7

= 20.2 km

∴Dinesh travelled 20.2 km

Distance travelled by Ayub = AD + DC

= 9.3 + 11.8

= 21.1 km

∴Ayub travelled 21.1km

Therefore, Ayub travelled more distance by = (21.1 – 20.2)

= 0.9 km

∴Ayub travelled 0.9 km more than Dinesh.

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