Math, asked by kaminidogra076, 4 days ago

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7

km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and

C is 11.8 km from D.
1.Distance travelled by Dinesh to reach C from A a) 19.2 km (b) 20.2 km (c) 21.2 km (d) 22.2 km
2. Distance travelled by Ayub to reach C from A (a) 19.1 km (b) 20.1 km (c) 21.1 km (d) 22.1 km
3. Who travelled more distance? (a) 0.7 km (b) 0.8 km (c) 0.9 km (d) 1 km
4. How much distance will be travelled by Dinesh if he would have returned to place A through

place D? (a) 41.1 km (b) 41.2 km (c) 41.3 km (d) 41.4 km​

Answers

Answered by shiney39
4

Step-by-step explanation:

Distance travelled by Dinesh = AB + BC = 7.5+12=19.5

Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1

Ayub travelled more than Dinesh .

difference=21.1-19.5=1.6

He travelled 1.6 km more than Dinesh

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