Math, asked by manojkmanojk776, 4 days ago

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D Distance travelled by Dinesh to reach C from A​

Answers

Answered by Shreyas235674
0

Answer:

here is the answer:-

Distance travelled by Dinesh = AB + BC = 7.5+12=19.5

Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1

Ayub travelled more than Dinesh .

difference=21.1-19.5=1.6

He travelled 1.6 km more than Dinesh

Step-by-step explanation:

Answered by βαbγGυrl
0

Answer:

Refer the attachment's!!

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