Question

Dinitrogen and dihydrogen react as
N2 + 3H2 ⇒2NH3
1. calculate the mass of NH3 produced if 200g of dinitrogen reacts with 100g of dihydrogen.
2.will any of reactant remains unreactant
3. if yes, calculate the mass

Answer 1

Answer:

Explanation:

From the equation, 1 mole (28 g) of dinitrogen reacts with 3 mole (6 g) of

dihydrogen to give 2 mole (34 g) of ammonia.

⇒ 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.

Given,

Amount of dihydrogen = 1.00 × 103g

Hence, N2 is the limiting reagent.

28 g of N2 produces 34 g of NH3.

Hence, mass of ammonia produced by 2000 g of N2= 2428.57 g

(ii) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 willremain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 103g – 428.6 g= 571.4 g