Dinitrogen and dihydrogen react with each odher to produce ammonia acording to following chemical equation: N,(8)+3H,(g)> 2NH, (e) (a) Calculate the mass of ammonia gas formed if 2.0 kg of nitrogengas reacts with 1.0 kg of hydrogen gas. b)Which of the two reactants is the limiting reagent and why ? (c)Which of the two reactants will remain unreacted and what will be the amount left unreacted ? [Ans.: m (NH,)= 2.571 kg, H, will remain unreacted its mass is 571.5 g]
Answers
Answered by
2
Answer:
N2(g) + 3H2(g) —> 2NH3(g)
28g 6g 34g
28 g of N2 reacts with 6g of H2 .
1g of N2 reacts with 6/28 g of H2
2000g of N2 will react with 2000× 6/28
= 428.57 of H2
but H2 is given 1 × 10³g is greater than 428.57 g
N2 is a limiting reagent and limits the production of ammonia
28g of N2 produces 34 g of NH3
1g of N2 produces 34/28 g of NH3
2000g of N2 will produce 34/28 × 2000
= 2428.57 g of NH3 .
(ii) H2 is excess so it remains unreacted
(iii) Mass of unreacted dihydrogen = 1000-428.57
=571.43g
Similar questions