Question

Dinitrogen and dihydrogen react with each other to produce ammonia then calculate the mass of ammonia produced in 2.00 into 10 to the power 3 gram nitrogen react with 1.00 into 10 to the power 3 gram of hydrogen

Answer 1

When dinitrogen and dihydrogen react with each other to produce ammonia,the reaction would be

N2+3H2———›2NH3

1mol of N2= 28 grams of N2

3 moles of H2= 6 grams of H2

2 moles of NH3 = 34 grams of NH3

here , we observed that,

28 g of N2 reacts with 6g of H2 .

so 1g of N2 reacts with 6/28 g of H2

so 2000 grams of N2 will react with 2000× 6/28 = 428.57 of H2

but H2 is given 1 × 10³gm > 428.57 gm

e.g., H2 is excess available .hence, N2 is the limiting reagent. it means N2 limits the production of amount of anomia .

28g of N2 produces 34 g of NH3

1g of N2 produces 34/28 g of NH3

2000g of N2 will be produce 34/28 × 2000 = 2428.57 gm of NH3.