Chemistry, asked by annammat400hydro, 8 months ago

dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical reaction. N2+3H2=2NH3. calculate the amount of ammonia produce if 2g of dinitrogen react with dihydrogen.

Answers

Answered by lutherking1702
2

Explanation:

=28.0 g

1 mol

Na(g)

+

=6.0 g

3 mol

3H

2(g)

=34.0 g

2 mol

2NH

3(g)

(i) 28.0 g of N

2

require 6.0 g of H

2

to produce

=34.0 g of NH

3

2.00×10

3

g of N

2

will produce

=

28

34

×2.00×10

3

g of NH

3

=2.43×10

3

g of NH

3

=2430 g NH

3

(ii) Yes, dihydrogen will remain unreacted to some extent

(iii) Amount of hydrogen that remains unreacted.

28.0 g of N

2

require 6.0 g of H

2

2.00 g×10

3

g of N

2

will require

=

28.0

6.0

×2.00×10

3

of H

2

=428.5 g of H

2

∴ Amount of hydrogen that remains unreacted

=[1.00×10

3

−428.5]

g

=571.5 g.

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