dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical reaction. N2+3H2=2NH3. calculate the amount of ammonia produce if 2g of dinitrogen react with dihydrogen.
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Explanation:
=28.0 g
1 mol
Na(g)
+
=6.0 g
3 mol
3H
2(g)
→
=34.0 g
2 mol
2NH
3(g)
(i) 28.0 g of N
2
require 6.0 g of H
2
to produce
=34.0 g of NH
3
2.00×10
3
g of N
2
will produce
=
28
34
×2.00×10
3
g of NH
3
=2.43×10
3
g of NH
3
=2430 g NH
3
(ii) Yes, dihydrogen will remain unreacted to some extent
(iii) Amount of hydrogen that remains unreacted.
28.0 g of N
2
require 6.0 g of H
2
2.00 g×10
3
g of N
2
will require
=
28.0
6.0
×2.00×10
3
of H
2
=428.5 g of H
2
∴ Amount of hydrogen that remains unreacted
=[1.00×10
3
−428.5]
g
=571.5 g.
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