Question

Dinosaur weighs 60,000 N stands on one foot of area 3000 cm2. How much pressure would it exert on the ground?

Answer 1

Explanation:

As per the provided information in the given question, we have :

• Force applied by the dinosaur (F) = 60,000 N
• Area (A) = 3000 cm²

We are asked to calculate the pressure exerted by it one the ground.

As we know that,

• Pressure is defined as force per unit area. That means,

$\underline{ \boxed{\sf {P= \dfrac{F}{A} }}}$

• P denotes pressure
• F denotes force
• A denotes area

Before commencing the steps, it must be in sure that the area should be in m², this is because SI unit of pressure is N/m² ( or Pascal ).

★ Converting 3000 cm² into m² :-

$\longrightarrow \sf {1 \; m^2= 10000 \; cm^2}$

$\longrightarrow \sf {1 \; cm^2= \dfrac{1}{1000}m^2 }$

$\longrightarrow \sf {3000 \; cm^2= \dfrac{1}{10000} \times 3000 \; m^2 }$

$\longrightarrow \sf {3000 \; cm^2= \cancel{ \dfrac{3000}{10000}} \; m^2 }$

$\longrightarrow \sf {3000 \; cm^2= \cancel{ \dfrac{3}{10}} \; m^2 }$

$\longrightarrow\boxed{ \sf {3000 \; cm^2=0. 3 \; m^2 }}$

$\therefore$ Area on which force applied is 0.3 m².

Now, substitute the values in the formula of pressure, that is :

$\longrightarrow \underline{ \boxed{\sf {P= \dfrac{F}{A} }}}$

$\longrightarrow \sf {P= \dfrac{60000 \; N}{0.3 \; m^2} }$

$\longrightarrow \sf {P= \dfrac{60000 \times 10 \; N}{3 \; m^2} }$

$\longrightarrow \sf {P= \cancel{ \dfrac{600000 \; N}{3 \; m^2} } }$

$\longrightarrow \sf {P= 200000 \; Pa }$

$\longrightarrow \underline{\boxed{\sf {P= 200 \; kPa }}} \; \bigstar$

$\therefore$ Pressure exerted by the dinosaur is 200 kPa.

Points to remember :

• Pressure is force per unit area.

• SI unit of pressure is Pascal (Pa).

• 1 Pa is equivalent to 1N/1m².

• Less the area, more the pressure will be.

• More the area, less the pressure will be.

• Less the force, more the pressure will be.