Math, asked by batwingmahir, 3 days ago

Dip's father is five times older han Dip. 12 years hence his lather will be 3 times oldur than Dip. Find their presernt ages​

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Answered by anishkumarsingh2022
2

Answer:

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A father is three times as old as his son. In 12 years time, he will be twice as old as his son. Find the present ages of father and the son.

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Solution

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Verified by Toppr

Let the present age of son =x

Then, the present age of father =3x

According to the question,

The age of son after 12 years =x+12

And the age of father after 12 years =2(x+12)

Therefore,

3x+12=2(x+12)

3x+12=2x+24

x=12

So, the present age of son is 12 years and present age of father is 36 years.

Answered by rohekog911
1

Answer:

dip age 12

dip father 60

Step-by-step explanation:

dip = x year

dip father = 5x

after 12 years dip = x +12

dip father = 3(x+12)

therefore 3(x+12) = 5x + 12

3x+36 = 5x + 12

2x = 24

x = 12

dip age 12

dip father 60

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