Chemistry, asked by vaishalikalamkar27, 3 days ago

Dipti was asked to prepare three separate mixtures in beakers A, B, and C, by mixing sugar, chalk powder, and soap powder respectively in water. What is the order of relative size of solute particles in solutions A, B, and C?

A. A>B>C
B. C>A>B
C. B>C>A
D. C>B>A​

Answers

Answered by rahul123437
2

RANGE OF RELATIVE SIZE OF PARTICLE ON DISSOLUTION IN MIXTURES

  • When sugar, chalk powder, and soap powder are mixed in separate beakers A, B, and C respectively the relative size of the particles will range as :
  • The largest size is of chalk powder particle (B), followed by soap powder (C), and sugar particles (A).

Therefore,             B > C > A  (OPTION C)

  • Sugar particles on dissolution with water will form a stable mixture. The particles will be completely dissolved and no particles can be seen separately in the solution.
  • Soap powders are soluble in water forming stable mixtures. The particle size will be relatively larger than the sugar particle but cannot be seen suspended in the solution.
  • Chalk powder consists of Calcium carbonate and will form an unstable mixture as it will not dissolve in water. The particles will remain suspended in the solution.
Answered by jotiirle
0

Answer:

correct option is C ( B >C >A )

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