Question

Dipti was asked to prepare three separate mixtures in beakers A, B, and C, by mixing sugar, chalk powder, and soap powder respectively in water. What is the order of relative size of solute particles in solutions A, B, and C?

A. A>B>C

B. C>A>B

C. B>C>A

D. C>B>A​

Answer 1

Answer:

C>B>A

Explanation:

AS WE ALL KNOW THE SOLUBILITY OF SOAP POWDER IS VERY LESS IN CAMPARE OF CHALK POWDER AND THE LEAST IS SUGAR

Answer 2

Given info : Dipti was asked to prepare three separate mixtures in beakers A, B, and C, by mixing sugar, chalk powder, and soap powder respectively in water.

To find : the order of relative size of solute particles in solutions A , B and C is ..

solution : we know, sugar is a compound and it forms solution so size of particles must be the smallest.  but chalk powder is very little soluble in water so it forms an suspension. soap powder in water is a colloidal solution.

we know the order of size is

                 suspension > colloidal > solution

here sugar (A) = solution

chalk powder (B) = suspension

soap powder (C) = colloid

so the order of relative size of solute particles in solutions ; B > C > A

therefore the correct option is (C)