direct answer please
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Answered by
1
The value of
1+b−ia
1+b+ia
=
(1+b−ia)(1+b+ia)
(1+b+ia)
2
=
(1+b)
2
+a
2
1+b
2
−a
2
+2iab+2b+2ia
=
1+b
2
+2b+a
2
1+2b+b
2
−a
2
+i(2ab+2a)
=
2+2b
a
2
+b
2
+2b+b
2
−a
2
+i2a(1+b)
=
2(1+b)
2b
2
+2b+i2a(1+b)
=
2(1+b)
2b(1+b)
+i
1+b
a(1+b)
=b+ia
Answered by
0
-3/4 is the answer.
hope it helps you☺️
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