Question

Direction For Question : (31 - 32) Orange trees thrive in warm, Mediterranean climates where there is no threat of frost. This full-sun plant produces the best fruit when provided with optimal moisture, light and nutrition, in the form of fertilization. Orange trees require fertilization three times per year. You need to increase fertilizer amounts as the tree ages and becomes established. Complete nutrition is essential for a healthy tree.
A fruit grower can use two types of fertilizer in an orange grove, brand A and brand B. Each bag of brand A contains 8 pounds of nitrogen and 4 pounds of phosphoric acid. Each bag of brand B contains 7 pounds of nitrogen and 7 pounds of phosphoric acid. Tests that the grove needs 720 pounds of nitrogen and 500 pounds of phosphoric acid.

31. How many bags of brand A should be used to provide the required amounts of nitrogen and how acid? a) 35 bags b) 55 bags c) 28 bags d) 40 bags

32. How many bags of brand B should be used to provide the required amounts of nitrogen and phos acid? a) 35 bags b) 55 bags c) 28 bags d) 40 bags

I'll give you 30 points​

Answer 1

Step-by-step explanation:

trees warm. bags of social work

Answer 2

Given:

Amount of nitrogen in a bag of brand A fertilizer = 8 pounds

Amount of nitrogen in a bag of brand B fertilizer = 7 pounds

Amount of phosphoric acid in a bag of brand A fertilizer = 4 pounds

Amount of phosphoric acid in a bag of brand B fertilizer = 7 pounds

Total quantity of nitrogen needed to fertilize orange grove = 720 pounds

Total quantity of phosphoric acid needed to fertilize orange grove = 500 pounds

To find:

No. of bags of brand A to provide required amounts of nitrogen and phosphoric acid.

No. of bags of brand B  to provide required amounts of nitrogen and phosphoric acid.

Solution:

Let no. of bags of brand A be $x$

Let no. of bags of brand B be $y$

Formulating the given information,

$8x+7y=720...(1)\\4x+7y=500...(2)$

Subtracting equation (2) from (1)

$4x=220$

$x=\frac{220}{4}$

$x=55$

Substituting the value of $x$ in equation (2)

$4x+7y=500$

$4(55)+7y=500$

$220+7y=500$

$7y=500-220$

$7y=280$

$y=\frac{280}{7}$

$y=40$

∴ $x=55, y=40$

Final Answer:

No. of bags of brand A required to provide fertilization to the grove is 55 bags. So, option (b) is the correct answer.

No. of bags of brand B required to provide fertilization to the grove is 40 bags. So, option (d) is the correct answer.

31. option (b) 55 bags

32. option (d) 40 bags