Question

Direction for questions 13 to 15
A stone is thrown vertically upwards from the
ground and caught at the same point on the
ground after 10 seconds. (Take, g = 10 m/s2)
The stone was thrown with a speed of​

Answer 1

Explanation:

Direction for questions 13 to 15

Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m

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