Direction for questions 13 to 15
A stone is thrown vertically upwards from the
ground and caught at the same point on the
ground after 10 seconds. (Take, g = 10 m/s2)
The stone was thrown with a speed of
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Explanation:
Direction for questions 13 to 15
Let u be the initial velocity and h be the maximum height attained by the stone.
v
1
2
=u
2
−2gh,
(10)
2
=u
2
−2×10×
2
h
100=u
2
−10h ....(i)
Again at height h,
v
2
2
=u
2
−2gh
(0)
2
=u
2
−2×10×h
u
2
=20h ... (ii)
So, from Eqs. (i) and (ii) we have
100=10h
h=10m
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