Question

Direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit)
(a) $a sin \theta = \frac{\lambda}{2}$
(b) $a cos \theta = \frac{3 \lambda}{2}$
(c) $a sin \theta = \lambda$
(d) $a sin \theta = \frac{3 \lambda}{2}$

Answer 1

hey....
option A is correct answer.....
mark me brainliest plz

Answer 2

Answer:

sin a=2n+1/2 lambda

sin a=2×1+1/2 lambda

sin a=3/2 lambda

4th option is correct.