Question

Direction (Q No. 126 to Q No. 133):
In a party there were 70 people who took tea. There were 80 people who took coffee. If there were
120 people in the party then,

126. What is the maximum possible number of people who took none of these two ?
a. 60
b. 30
c.40
d. None of the above

127. What is the maximum possible number of people who took exactly one of these two drinks

a/ 80
b. 90 c. 120 d. 100

128. What is the maximum possible number of people who took both of the tea and coffee?

a. 80
e 70 c. 90 d. 100

129. What is the maximum possible number of people who took at least one of these two drinks?

a. 120
b. 100 c. 90 d. None of the above

130. What is the minimum possible number who took both the drinks?

a. 40
b. 30 .50d . 20

131. What is the minimum possible number of people who took at least one of the two drinks?

a. 70
b. 40 C. 80 d. None of these

132. What is the minimum possible number of people who took at most one of the two drinks?
a. 40
b. 50 C. 60 d 70

133. What is the minimum possible number of people who took none of these two drinks 2
a. 20
b. 30 c40
d. None of the above
​

Answer 1

Answer:

i don't explain your question

Answer 2

Maximum possible number of people who took none of these two = 40

Step-by-step explanation:

Total People  =  P  = 120

People who Drink Tea = T  = 70

People who Drink Coffee = C  = 80

None  N = >

maximum possible number of people who took both of the tea and coffee = 70  

Max T∩C  = 70    Than Max None

=> P = T  + C  - T∩C  + None

=> 120 = 70 + 80 - 70  + None

=> 40

maximum possible number of people who took none of these two = 40

Minimum None = 0   None of the above

Then Min T∩C = ?

=> 120 = 70 + 80 - T∩C + 0

=> T∩C = 30

maximum possible number of people who took exactly one of these two drinks = T - T∩C  + C - T∩C   = 70 - 30 + 80 - 30  = 90

minimum possible number of people who took at most one of the two drinks  =   T - max T∩C + C - max T∩C +none

= 70 - 70  + 80 - 70 + 40

= 50  

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