Directions: Complete the two-column proof.
Given: AC bisects A and C
Prove: ΔABC ≅ ΔADC
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Solution :-
In ∆ABC and ∆ADC , we have,
→ ∠BAC = ∠DAC { given that, AC bisects ∠A .}
→ AC = AC (common)
→ ∠BCA = ∠DCA { given that, AC bisects ∠C.}
then,
→ ∆ABC ≅ ∆ADC { By ASA congruence rule. }
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