Math, asked by nainsitailor, 8 months ago

Directions: (Q.48 TO 52): Four players A, B, C and D are holding 4 cards each. Each of them has an Ace, a King, a Queen
and a Jack. All of them have all the suits (spades, hearts, clubs, and diamonds)
i. A has Ace of spades and Queen of diamonds. ii. B has Ace of clubs and King of diamonds.
ili. C has Queen of clubs and King of spades. iv. D has Jack of clubs.
48. Ace of diamonds is with
(A) A (B) B (C)C (D)D
49. Jack of hearts is with
(A) A (B) E (C) C (D) D
50. Queen of spades is with
(A) A (B) B (C) C (D)D
51. C has which of the following with him?
(A) Ace of hearts (B) Jack of spades (C) King of hearts (D) Queen of spades
52. D has which of the following with him?
(A) Ace of hearts (B) Queen of hearts (C) King of hearts (D) King of clubs

Answers

Answered by neha6415
5

Step-by-step explanation:

I think it can help you Its simple and my teacher my this doubt just two days before

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Answered by sarahssynergy
5

Given:

  • 4 Players A, B, C, and D hold 4 cards each with each having Ace, King, Queen, and Jack.
  • A has Ace of spades, Queen of Diamonds.
  • B has Ace of clubs and King of Diamonds
  • C has the Queen of clubs and King of spades
  • D has the jack of clubs

Step-by-step explanation:

To find the solution, we require a table that helps us to find/identify the cards among the players.

  1. Ace of Diamonds is with D (option D)
  2. Jack of Hearts is with A (option A)
  3. Queen of spades is with D (option D)
  4. C has Ace of Hearts(option A) with him
  5. D has King of Hearts(option C) with him
Attachments:
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