Directions: Read the given passage carefully and find the answer of the following question LCM of two numbers A and B is 60. B is a 2 digit number which leaves remainder as 2 when divided by 6. It is also given B>A
Answers
Answered by
1
Given :
LCM of two numbers A and B is 60
B is a 2 digit number which leaves remainder as 2 when divided by 6
To Find:
A & B
Solution:
let A & B be two numbers
Given that,
B is a 2 digit number which leaves remainder as 2 when divided by 6
12 is the only number which leaves 2 as reminder when divided by 6
so, B = 12
LCM of 60 = 2 × 2 × 3 × 5
we know that one of the number is 12,then
LCM of 60 = 12 × 5
so , the another number is 5
12>5 which satisfoes the condition given in question
A = 5 & B=12
Answered by
6
Answer:
First number, say A, is 3 and second number, say B, is 20.
Step-by-step explanation:
Given that:
- The LCM of given two numbers is 60.
- B is two digit number.
- B > A.
- B when divided by 6, gives remainder 2.
Let, the first number be A and second number is B.
- LCM of A and B is 60.
- Factorisation of 60 gives:
- Two numbers A and B must be the factor of 60.
Considering possible factors we get:
- Case 1: A = 2 x 2 = 4 and B = 3 x 5 = 15.
- This case does not satisfied our conditions.
- Case 2: A = 3 and B = 2 x 2 x 5 = 20.
- This case does satisfy all of the above conditions.
Condition Checking:
- B = 20 is a two digit number.
- B > A, i.e. 20 > 3.
- 20 divided by 6 leaves remainder 2.
- LCM of 3 and 20 is 60.
Hence, A = 3 and B = 20.
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