Math, asked by sarikkhullar99, 4 days ago

Directions: Read the given passage carefully and find the answer of the following question LCM of two numbers A and B is 60. B is a 2 digit number which leaves remainder as 2 when divided by 6. It is also given B>A

Answers

Answered by RizwanaAfreen
1

Given :

LCM of two numbers A and B is 60

B is a 2 digit number which leaves remainder as 2 when divided by 6

To Find:

A & B

Solution:

let A & B be two numbers

Given that,

B is a 2 digit number which leaves remainder as 2 when divided by 6

12 is the only number which leaves 2 as reminder when divided by 6

so, B = 12

LCM of 60 = 2 × 2 × 3 × 5

we know that one of the number is 12,then

LCM of 60 = 12 × 5

so , the another number is 5

12>5 which satisfoes the condition given in question

A = 5 & B=12

Answered by abhijattiwari1215
6

Answer:

First number, say A, is 3 and second number, say B, is 20.

Step-by-step explanation:

Given that:

  • The LCM of given two numbers is 60.
  • B is two digit number.
  • B > A.
  • B when divided by 6, gives remainder 2.

Let, the first number be A and second number is B.

  • LCM of A and B is 60.
  • Factorisation of 60 gives:

60 = 2 \times 2 \times 3 \times 5

  • Two numbers A and B must be the factor of 60.

Considering possible factors we get:

  • Case 1: A = 2 x 2 = 4 and B = 3 x 5 = 15.
  • This case does not satisfied our conditions.

  • Case 2: A = 3 and B = 2 x 2 x 5 = 20.
  • This case does satisfy all of the above conditions.

Condition Checking:

  • B = 20 is a two digit number.
  • B > A, i.e. 20 > 3.
  • 20 divided by 6 leaves remainder 2.
  • LCM of 3 and 20 is 60.

Hence, A = 3 and B = 20.

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