Question

Discrepancy of d/dx (x⁴+3x+4)=?​

Answer 1

Answer:

$Y= {x}^{4} + 3x + 4$

$\frac{dy}{dx} = \frac{d( {x}^{4}) }{dx} + \frac{d(3x)}{dx} + \frac{d(4)}{dx}$

$\frac{dy}{dx} = 4x {}^{3} + 3(1) + 0$

$\frac{dy}{dx }= 4 {x}^{3} + 3$

Be Brainly!