Question

discriminant of the quadratic equation 2xsquare - 6 X + 8 = 0​

Answer 1

2x² - 6x + 8 = 0

2 ( x² - 3x + 4 ) = 0

x² - 3x + 4 = 0

a = 1, b = -3, c = 4

D = (-3)² - 4 × 1 × 4

D = 9 - 16

D = -7

Answer 2

Discriminant of the quadratic equation $2x^2-6x+8=0$ is $\sqrt{-7}$

Explanation:

The polynomial equations of degree two in one variable of type f(x) = $ax^2 + bx + c = 0$ and with $a,b,c\in R$ and a≠0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f(x). The roots of the quadratic equation are the values of x that fulfil the equation. It is a given that the quadratic equation has two roots. Roots can have either a true or imaginary nature.

Given the quadratic equation is $2x^2-6x+8=0$

Also

$2x^2-6x+8=0\\\Rightarrow x^2-3x+4=0$

We know, Discriminant $D=\sqrt{b^2-4ac}$

Comparing $x^2-3x+4=0$ with $ax^2+bx+c=0$

$a=1, b=-3, c=4$

$\therefore D=\sqrt{(-3)^2-(4\times 1\times 4)}\\\Rightarrow D=\sqrt{9-16}\\\therefore D=\sqrt{-7}$

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