Discuss equilibrium of rigid bodies.
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A rigid body will be in equilibrium if the following two conditions are met.
The sum of the forces acting on the body must be zero.The net torque acting on the body must be zero.
Translational Equilibrium
For an object to be in translational equilibrium the vector sum of the forces acting on it must be zero. Starting that the vector sum of forces acting on an object is zero is equivalent to:
∑Fx=0,∑Fy=0,∑Fz=0.
Where Fx , Fy and Fz are the components of a force F in three perpendicular directions. It means that all the force along the x-axis add to zero. Same is true for forces along y and z axis. From Newton’s second law of motion,
F=maFor translational motion,F=0,soor,0=maor,a=0or,v=constant
Thus, when a body is in transitional equilibrium, it ie either at rest or it is moving with constant velocity.
hope this will helps u
The sum of the forces acting on the body must be zero.The net torque acting on the body must be zero.
Translational Equilibrium
For an object to be in translational equilibrium the vector sum of the forces acting on it must be zero. Starting that the vector sum of forces acting on an object is zero is equivalent to:
∑Fx=0,∑Fy=0,∑Fz=0.
Where Fx , Fy and Fz are the components of a force F in three perpendicular directions. It means that all the force along the x-axis add to zero. Same is true for forces along y and z axis. From Newton’s second law of motion,
F=maFor translational motion,F=0,soor,0=maor,a=0or,v=constant
Thus, when a body is in transitional equilibrium, it ie either at rest or it is moving with constant velocity.
hope this will helps u
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