Question

discuss how will you factor 11x+19x-6​

Answer 1

Answer:

Now, 11x² + 19x - 6

= 11x² + (22 - 3)x - 6

= 11x² + 22x - 3x - 6

= 11x (x + 2) - 3 (x + 2)

= (x + 2) (11x - 3),

which is the required factorization.

Answer 2

Explanation:

The first term is, 11x2 its coefficient is 11 .

The middle term is, -19x its coefficient is -19 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 11 • -6 = -66

Step-2 : Find two factors of -66 whose sum equals the coefficient of the middle term, which is -19 .

-66 + 1 = -65

-33 + 2 = -31

-22 + 3 = -19 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -22 and 3

11x2 - 22x + 3x - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

11x • (x-2)

Add up the last 2 terms, pulling out common factors :

3 • (x-2)

Step-5 : Add up the four terms of step 4 :

(11x+3) • (x-2)

Which is the desired factorization