discuss how will you factor 11x+19x-6
Answers
Answer:
Now, 11x² + 19x - 6
= 11x² + (22 - 3)x - 6
= 11x² + 22x - 3x - 6
= 11x (x + 2) - 3 (x + 2)
= (x + 2) (11x - 3),
which is the required factorization.
Explanation:
The first term is, 11x2 its coefficient is 11 .
The middle term is, -19x its coefficient is -19 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 11 • -6 = -66
Step-2 : Find two factors of -66 whose sum equals the coefficient of the middle term, which is -19 .
-66 + 1 = -65
-33 + 2 = -31
-22 + 3 = -19 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -22 and 3
11x2 - 22x + 3x - 6
Step-4 : Add up the first 2 terms, pulling out like factors :
11x • (x-2)
Add up the last 2 terms, pulling out common factors :
3 • (x-2)
Step-5 : Add up the four terms of step 4 :
(11x+3) • (x-2)
Which is the desired factorization