Discuss in detail the characters of the story A Flight of Pigeons.
Answers
Answer:
Answer:
Given parameters
Mass of the engine (M) = 8000 kg
Number of wagons = 5
Mass of the wagons (m) = 2000 kg
Force exerted by the engine (F ) = 40000 N
Frictional force offered by the track (Ff) = 5000 N
(a) Net accelerating force (Fa) = F – Ff
Fa = 40000 N – 5000 N
Fa = 35000 N
(b) Let us consider the acceleration of the train be a m/s2
Acceleration is the ratio of net acceleration force by mass, i.e
a = Fa/m
Where m is the mass of the train, it can be calculated as follows
Total mass of the train (m) = Mass of the engine + (Mass of the wagons × Number of wagons)
m = 8000 + (5 × 2000)
m = 18000 kg
Acceleration of the train (a) = 35000/18000
a = 1.944m/s2
(c) The external force is only applied to waggon 1 directly. On the last four waggons, the net force is equal to the force added to waggon 2 by waggon 1.
Let us consider the acceleration of the wagons is aw
35000 = 5m × aw
aw = 35000/5m
aw = 35000/(5 × 2000)
aw = 3.5 m/s2
Then the mass of last four wagons can be considered as mw
mw = 2000 × 4
mw = 8000 kg
Now let us calculate the net force on the last four wagons
F’ = mw× aw
F’ = 8000 × 3.5
F’ = 28000 N
∴ The force of wagon-1 on the wagon-2 is 28000N15,SOLUTION:
i) 15,45,40,120
we have 15,45,40,120
ratio of 15 to 45=\frac{15}{45}=\frac{15\div15}{45\div15}=\frac{1}{3}=1:3
45
15
=
45÷15
15÷15
=
3
1
=1:3
[HCF OF 40 and 15, 45 is 15]
ratio of 40 to 120=\frac{40}{120}=\frac{40\div40}{120\div40}=\frac{1}{3}=1:3
120
40
=
120÷40
40÷40
=
3
1
=1:3
[HCF of 40 and 120 is 40]
here, 15:4=40:120=1:3
ii) 33, 121,9,96
we have 33,121,9,96
ratio of 33 to121 = \frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}
121
33
=
121÷11
33÷11
=
11
3
ratio of 9 and 96= \frac{9}{96}=\frac{9\div3}{96\div3}=\frac{3}{32}
96
9
=
96÷3
9÷3
=
32
3
[HCF of 9 and 96 is 3]
here, 3:11\ne3:323:11
=3:32
i.e\ 33:121\ne9:96i.e 33:121
=9:96
therefore, 31,121,9 and 96 are not in proportion.
iii) 24,28,36,48
ratio of 24 and 28 is \frac{24}{28}=\frac{24\div4}{28\div4}=\frac{6}{7}=6:7
28
24
=
28÷4
24÷4
=
7
6
=6:7
[HCF of 36 and 48 is 12]
- In the novel, Hester and Dimmesdale are two married lovers who are devoted to each other despite the many obstacles they encounter.
- They end up getting a divorce, but Hester and Dimmesdale are very much in love and remain devoted to one another, even after they are divorced.
- It is important to recognize that Hester and Dimmesdale are victims of circumstance, and their destruction over the course of the novel is a result of both personal and social factors.
- In chapter twenty-two, for example, Hester is reminded of how much damaging gossip and news reporting is available.
- This causes self-doubt and results in a downward spiral of despair.
- In the end, Hester decides to destroy the evidence of her adulterous relationship with Dimmesdale by burning his letters.
- In the novel, Dimmesdale and Hester’s relationship is fragile since they are unsure of their feelings.
- The novel's plot clearly shows that Dimmesdale is an unreliable character, and Hester marries Dimmesdale in the hope that he will reform.
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