Discuss the condition for the maximum range of a projectile. Show that for a given velocity of projection, there are two angles of projection which give the same range of projectile.
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Range of projectile is given by
R=2u^2sin2theta/g
Rmax when theta is max as sintheta have max value 1
sin2theta=1
2theta=90
theta=45 that is when theta is 45 Range is max
R=u^2/g
R=2u^2sin2theta/g
Rmax when theta is max as sintheta have max value 1
sin2theta=1
2theta=90
theta=45 that is when theta is 45 Range is max
R=u^2/g
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