Question

discuss the electrolysis of copper sulphate solution​

Answer 1

Answer:

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Explanation:

Electrolysis of Copper(II) Sulphate Solution

This experiment is designed to demonstrate the different products obtained when the electrolysis of copper(II) sulfate solution is carried out first with inert graphite electrodes and then with copper electrodes. The use of copper electrodes illustrates how copper is refined industrially.

Using Graphite Rods

1. Set up an electrolysis cell using graphite rods as electrodes and copper(II) sulphate solution as electrolyte.

2. At the anode: Bubbles of gas (oxygen) are formed at the anode.

Anode reaction: 4OH-(aq) → O2(g) + 2H2O(l) + 4e-

3. At the cathode: A deposit of copper forms on the cathode; this will often be powdery and uneven.

Cathode reaction: Cu2+(aq) + 2e- → Cu(s)

Using Copper Plates (Refining Copper)

1. Replacing the graphite rods with clean copper plates produces a different anode reaction.

2. At the anode: No oxygen is produced, rather the copper anode dissolves.

Anode reaction: Cu(s) → Cu2+(aq) + 2e-

3. At the cathode: A deposit of copper forms on the cathode.

Cathode reaction: Cu2+(aq) + 2e- → Cu(s)

During this electrolysis, the mass gained of copper at the cathode is equal to the mass lost at the anode.

Answer 2

Electrolysis of Copper Sulphate solution:-

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Needs for the experiment:-

1. Saturated solution of copper(1 1) sulphate
2. Con.Sulphuric acid
3. Platinum
4. Aqueous copper sulphate

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Now Saturated solution of copper (11) sulphate,prepared in distilled water a small amount of con.Sulphuric acid.

Important question which can be asked:-

Why do we use Con.Sulphuric Acid?

Answer:-We use con.Sulphuric acid to increase the electrical conductivity of electrolyte.

For Electrodes : Cathode : Platinum

Anode: Platinum

Particle presents are:-Cu²+ , H+,So4²-,OH- and H2O molecule.

Ions present:

Cu²+,H+,So4²- and OH-

Now after heating the solution

Reaction at anode:-

• The So4²- and OH- ions both get migrate to the anode.
• Discharge to form neutral (OH) radiation.
• Copper ions discharge in preference to (H+) ions to form neutral copper atoms.
• Copper atom deposit themselves on cathode.

Reaction at anode:-

• So4³- and OH- ions migrate to the anode.
• OH- being lower in electrochemical series so discharge to form (OH) radical.
• It forms water and oxygen.

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Product at anode:

Oxygen

Product at cathode:

Pink or reddish brown copper is deposited

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Things which we will find after reaction:-

1. Deposition of Cu ions completed then electrolysis take place.
2. Hydrogen is liberated at cathode.
3. Oxygen is liberated at anode.