Question

*discuss the formation of bond in O3 and SO3 *​

Answer 1

Answer:

n SO3 sulphur will be the central atom and will have three double bonds with oxygen. The sigma bond (single bond) is between the sp2 orbital on Sulphur and another sp2 on Oxygen. The double bond is created between the empty p orbital of Sulphur and an empty p orbital of Oxygen.

Name of the Molecule: Sulphur Trioxide

Bond Angle: 120o

Hybridization Type: sp2

Explanation:

Answer 2

Answer:

When an oxygen molecule receive a photon (h\nu), it dissociates into monoatomic (reactive) atoms. These atoms attack an oxygen molecule to form ozone, O3. A dynamic equilibrium is established in these reactions. ... bond energy of the bent ozone molecule O=O=O

Explanation:

SO3 is a combination of two elements one Sulphur and three Oxygen atoms. To understand the hybridization of sulphur trioxide we have to understand the bonding between sulphur and oxygen. If we draw and look at the Lewis structure sulphur will be the central atom and will have three double bonds with oxygen. In this, there is one sigma and one pi bond formed. This gives us the sp2 hybridization type.