Question

Discuss the formation of i) Na-Cl ii) H2O iii) Cl-Cl​

Answer 1

$Bond formation in Sodium Chloride (NaCl)</p><p></p><p>NaCl is an ionic solid.</p><p></p><p>The general electronic configurations are...</p><p></p><p>Na−1S22S22P63S1</p><p></p><p>Cr−1S22S22P63S23P5</p><p></p><p>Na is in excess of one electron to attain octet configuration.</p><p></p><p>Cl has one electron less to attain octet configuration.</p><p></p><p>So, the excess one electron is transferred to a chlorine atom from Na(sodium) atom and thus an ionic bond is formed due to the transfer of electrons. Chloride being a mole electronegative atom than sodium tends to attract the shared electron pair towards itself.</p><p></p><p>Thus NaCl has Na+ and Cl− atoms.</p><p></p><p>Na+−Cl−</p><p></p><p>Chloride attains octet configuration by gaining on the electron.</p><p></p><p>Sodium attains octet configuration by losing the electron.</p><p> </p><p>Thus Ionic solid NaCl is stable. </p><p></p><p>$

Answer 2

Answer:

I.) Na-Cl is ans

Explanation:

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