Question

Discuss the internal change for reversible heating of pure gas at constant p

Answer 1

Answer:

Explanation:

Pure gas at constant P

So it's an isobaric process. Always nCvdT is internal energy

Since it's a physics question Q= U + W

Qp = nCvdT + PdV. (Qp is heat given at constant pressure)

PdV = nRdT ( since pressure is constant)

So U = Qp - nRdT

Wait it doesn't end here

We know Q = nCdT then Qp= nCpdT

From the equations you can also see that Cp = Cv+ R